I must confess it turned out much less elegant than I thought it might - maybe some erlang or other functional gurus can point out a better algorithm.

Now before you all comment, yes I know most of the below isn't tail recursive - but performance isn't really the issue here, and a binary tree implementation in erlang is going to be inefficient anyway if you're making frequent updates, since every recursion will involve copying some of the structure (maybe it optimises that away ... dunno enough about its internals to comment).

-module(tree).
-export([find/2, tree_of_squares/1, insert/3]).

-record(node, {key, val, left = nil, right = nil, height = 1}).

%% find/1
find(SearchKey, Node) whenSearchKey == Node#node.key ->
  {ok, Node#node.val};

find(_, nil) ->
       not_found;

find(SearchKey, Node) whenSearchKey < Node#node.key ->
  find(SearchKey, Node#node.left);

find(SearchKey, Node) ->
  find(SearchKey, Node#node.right).


%% tree_of_squares/1 : make a tree where key = val and contains
%% squares of all numbers from 1 to Maxtree_of_squares(Max) ->
  tree_of_squares(Max, nil).


tree_of_squares(0, Tree) ->
  Tree;

tree_of_squares(Max, Tree) ->
  insert(Max * Max, Max * Max, tree_of_squares(Max - 1, Tree)).

%% insert/3 : return a new tree made from inserting (or updating)
%% a node of Key, Val into existing tree or new tree (nil)
insert(Key, Val, nil) ->
       #node{ key = Key, val = Val };

insert(Key, Val, Node) whenKey == Node#node.key ->
       Node#node{ val = Val };

insert(Key, Val, Node) whenKey < Node#node.key ->
       balance(Node#node{ left = insert(Key, Val, Node#node.left)});

insert(Key, Val, Node) ->
       balance(Node#node{ right = insert(Key, Val, Node#node.right)}).

%% height/1 : return the height of the tree
height(nil) ->
       0;
height(Node) whenNode#node.left == nil, Node#node.right == nil ->
       1;

height(Node) ->
       height(1, Node#node.left, Node#node.right).

height(Acc, Left, Right)
 whenLeft == nil;
      Right#node.height > Left#node.height ->
       Acc + Right#node.height;

height(Acc, Left, _) ->
       Acc + Left#node.height.


%% balance/1 : return a new tree which is the balanced version of Tree
%% note also that balance is trusted to always return the root height set
%% correctly
balance(nil) ->
  nil;

balance(Node) whenNode#node.left == nil, Node#node.right == nil ->
       Node#node{ height = height(Node)};

balance(#node{ left = L, right = R} = Node) whenL#node.height ==
R#node.height ->
       Node#node{ height = height(1, L, R)};

balance(#node{ left = L, right = R} = Node)
 whenR == nil ;
      L#node.height + 1 > R#node.height ->
       swing_right(Node);


balance(#node{ left = L, right = R} = Node)
 whenL == nil ;
      R#node.height + 1 > L#node.height ->
  swing_left(Node).

swing_left(#node{right = #node{ left = RL, right = RR } = Right} = Node)

 whenRR == nil ; RR == nil, RL == nil ;
      RL#node.height > RR#node.height ->

       move_left(Node#node{right = move_right(Right)});

swing_left(Tree) ->
       move_left(Tree).

swing_right(#node{left = #node{ left = LL, right = LR} = Left} = Node)

 whenLL == nil ; LL == nil, LR == nil ;
      LR#node.height > LL#node.height ->

       move_right(Node#node{ left = move_left(Left)});

swing_right(Tree) ->
       move_right(Tree).


move_left(Node)
 whenNode == nil ;
      Node#node.left == nil, Node#node.right == nil ->
       Node;

move_left(#node{ right = #node{ left = RL } = Right} = Node) ->

       OldRoot = Node#node{ right = RL },
       NewRoot = Right#node{ left = OldRoot#node{ height = height(OldRoot)}},
       NewRoot#node{ height = height(NewRoot) }.


move_right(Node)
 whenNode == nil ;
      Node#node.left == nil, Node#node.right == nil ->
       Node;

move_right(#node{ left = #node{ right = LR } = Left } = Node) ->

       OldRoot = Node#node{ left = LR},
       NewRoot = Left#node{ right = OldRoot#node{ height = height(OldRoot)}},
       NewRoot#node{ height = height(NewRoot) }.

1> c(tree).
{ok,tree}
2> T = tree:tree_of_squares(7).
{node,25,
      25,
      {node,9,
            9,
            {node,4,4,{node,1,1,nil,nil,1},nil,2},
            {node,16,16,nil,nil,1},
            3},
      {node,36,36,nil,{node,49,49,nil,nil,1},2},
      4}

3> tree:find(1, T).
{ok,1}
4> tree:find(2, T).
not_found

5> T2 = tree:insert(5, bar, tree:insert(4, foo, T)).
{node,25,
      25,
      {node,9,
            9,
            {node,4,foo,{node,1,1,nil,nil,1},{node,5,bar,nil,nil,1},2},
            {node,16,16,nil,nil,1},
            3},
      {node,36,36,nil,{node,49,49,nil,nil,1},2},
      4}
6> tree:find(5, T2).
{ok,bar}

An implementation of red-black trees is left as an exercise for the reader ;)

Computer Science is no more about computers than astronomy is about telescopes.

--E. W. Dijkstra

Great quote from the introduction of Algorithms with Perl

Unfortunately it seems noone at Apple is nearly that cool:

Failed to resolve the name of server bric-a-brac.apple.com to connect

There are surprisingly few results, but even worse is that the second search result is:

So any prospective collaborator or employer discovers that I have an un-done todo dating back to March 5 2003! And there's not even any comments suggesting what needs fixing. Oh well, it's in use in hundreds of production systems with tens of thousands of users, so I guess it doesn't really need fixing after all!

INI_FILE=path/to/file.ini
INI_SECTION=TheSection

eval `sed -e 's/[[:space:]]*\=[[:space:]]*/=/g' \
    -e 's/;.*$//' \
    -e 's/[[:space:]]*$//' \
    -e 's/^[[:space:]]*//' \
    -e "s/^\(.*\)=\([^\"']*\)$/\1=\"\2\"/" \
   < $INI_FILE \
    | sed -n -e "/^\[$INI_SECTION\]/,/^\s*\[/{/^[^;].*\=.*/p;}"`

NB: the eval is a ksh builtin. I imagine using declare in bash will achieve the same, but I haven't tested it.

NB2: it seems Solaris sed isn't quite up to the task - the above requires gnu sed.